carilah turunanke-3 fungsi berikut 4x3+2x2+4x+5
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f(x) = 4x³ + 2x² + 4x + 5
Turunan Pertama
f'(x) = 3 . 4x³-¹ + 2.2x²-¹ + 4
f'(x) = 12 x² + 4x
Turunan Kedua
f''(x) = 2 . 12x²-¹ + 4
f"(x) = 24x
Turunan Ketiga
f'''(x) = 1 . 24x¹-¹
f'''(x) = 1 . 24x⁰
f'''(x) = 24
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